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sum_of_square_of_deviation_from_mean = sum([(x - mean)**2 for x in arr])
var = sum_of_square_of_deviation_from_mean/n
std = math.sqrt(var)
print(round(std, 1))
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Day 1: Standard Deviation
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Easiest Solution
def stdDev(arr): n = len(arr) mean = sum(arr)/n