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My C# algorithm times out for the three last cases.
Is there a way to avoid checking the global connectivity of both T (through T and U) and D (through D and U) each time I assign a U to either T or D?
Separate the chocolate
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My C# algorithm times out for the three last cases. Is there a way to avoid checking the global connectivity of both T (through T and U) and D (through D and U) each time I assign a U to either T or D?