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Sherlock and Array

  • shubhamgoyal1101 + 4 comments

    python 3 code, easy to understand :) . It takes linear time 

    def solve(a):
    # Complete this function
    summy=sum(a)
    l=len(a)
    lefty=0
    for i in range(len(a)):
        current=a[i]
        summy-=current
        if lefty==summy:
            return 'YES'
        lefty+=current
    return 'NO'
    • martinberoiz + 0 comments

      loved it

    • Ajey01 + 0 comments

      great !!! best solution ..

    • nicmakaveli + 1 comment

      I had a similar idea, but yours is way better. Helped me figure out why mine was so slow:

      def solve(a):
    # Complete this function
    if len(a) == 1:
        return "YES"
    for i in range(1, int(len(a)+1/2)):
        left = sum(a[:i])
        right = sum(a[i+1:])
        if left == right:
            return "YES"
            break
    else:
        return "NO"

      Instead of computing the sum each time, just subtract. Way more efficient. Thank you for sharing.

    • mike_buttery + 0 comments

      Nice work!

      My first try was to sum both sides of the pivot and I timed out

      Then realised sum the whole array and + / - the pivot

      I iterated over the array rather than use indexes

      def balancedSums(arr):
    leftsum = 0
    rightsum = sum(arr)
    for n in arr:
        rightsum -= n
        if rightsum == leftsum:
            return 'YES'
        leftsum += n
    return 'NO'