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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Sherlock and Squares
  5. Discussions

Sherlock and Squares

  • sashivijaya
     + 0 comments

    java solution,

    double aRoot = Math.ceil(Math.sqrt(a));
        double bRoot = Math.floor(Math.sqrt(b));
        return Double.valueOf(bRoot - aRoot + 1).intValue();