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  1. Practice
  2. Algorithms
  3. Greedy
  4. Sherlock and The Beast
  5. Discussions

Sherlock and The Beast

  • Richard19Perez77 + 1 comment

    I am not sure, did you check my solution in Java, I am sure you have access to my solutions? Sorry I am not very skilled in C++, I have worked only with C# and Java for the last 3 years.

    • AnuragPatil + 2 comments

      Thanks for trying

      int main(){

      int t;
cin >> t;
for(int a0 = 0; a0 < t; a0++){
    int n, y, z, flag = -1;
    cin >> n;
    z = n;
    if(z <= 0)
        cout<<"-1\n";
    else
 {
    if(z%3 == 0)
        {
        cout<< string(z,'5')<<"\n";
    }
    while(z%3 != 0)
        {
        z -= 5;
     if(z<0)
            {
            cout<<"-1\n";
            break;
        }
    else
        {
        cout<<string(z,'5')<<string((n-z),'3')<<"\n";;
    }
    }
 }
}
return 0;

      }

      This is what i ment exactly, but still not working for large inputs :(

      • achyuthreddy_15 + 0 comments

        same with me

      • sanchitpatiyal95 + 1 comment

        changes to your code and its working for all test cases

        int main(){

        int t;
cin >> t;
for(int a0 = 0; a0 < t; a0++)
{

int n, y, z, flag = -1;
 cin >> n;
z = n;
 if(z <= 0)
cout<<"-1\n";
else
{
if(z%3 == 0)
{
cout<< string(z,'5')<<"\n";
}
while(z%3 != 0)
{
z -= 5;
if(z<0)
{
 cout<<"-1\n";
        break;
    }
    else
        {
        if(z%3==0)
             cout<<string(z,'5')<<string((n-z),'3')<<"\n";
    }
}


}
}
return 0;

        }

        • Astrodynamic + 0 comments
          #include <bits/stdc++.h>

using namespace std;

int main(void) {
    int t;
    cin >> t;
    for (int i = 0; i < t; i++) {
        int n, z;
        cin >> n;
        z = n;
        
        if(z % 3 == 0) {
            cout << string(z, '5') << endl;
        }
        while(z % 3 != 0) {
            z -= 5;
            if(z < 0) {
                cout<< "-1" << endl;
                break;
            } else {
                if(z % 3 == 0)
                    cout << string(z, '5') << string((n - z), '3') << endl;
            }
        }        
    }
    return 0;
}