We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Java Varargs - Simple Addition
Java Varargs - Simple Addition
Sort by
recency
|
310 Discussions
|
Please Login in order to post a comment
java15:
import java.io.; import java.lang.reflect.; import java.util.*;
class Add { public void add(int... numbers) { int sum = 0; StringBuilder sb = new StringBuilder(); for (int i = 0; i < numbers.length; i++) { sum += numbers[i]; sb.append(numbers[i]); if (i != numbers.length - 1) { sb.append("+"); } } sb.append("=").append(sum); System.out.println(sb); } }
public class Solution { public static void main(String[] args) { try { Scanner sc = new Scanner(System.in); int n1 = sc.nextInt(); int n2 = sc.nextInt(); int n3 = sc.nextInt(); int n4 = sc.nextInt(); int n5 = sc.nextInt(); int n6 = sc.nextInt(); Add ob = new Add(); ob.add(n1, n2); ob.add(n1, n2, n3); ob.add(n1, n2, n3, n4, n5); ob.add(n1, n2, n3, n4, n5, n6);
}
class Add{
}
Here is Java Varargs - Simple Addition solution - https://programmingoneonone.com/hackerrank-java-varargs-simple-addition-solution.html