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# Simple Array Sum

# Simple Array Sum

3rdboss + 19 comments This sh*t ain't for beginners like myself

nelson5 + 2 comments hahaha I feel you!

t2017anuragHackerRank Admin + 0 comments [deleted]fatullaev_marat + 2 comments def simpleArraySum(n, ar): thesum = 0 for i in ar: thesum += i return thesum

karlovskaya + 1 comment Regarding using for..in this is worth to read https://stackoverflow.com/questions/500504/why-is-using-for-in-with-array-iteration-a-bad-idea

ahmer9800 + 0 comments Thanks for posting this link.

293303043nathan + 0 comments why deos it keep saying that im have a system error i know i am codeing right

mjd06h + 4 comments This is my noob code. It is not glamorous but it passed the tests

def simpleArraySum(n, ar): m = 1 a = ar[0] while m < n: a = a + ar[m] m = m + 1 return a

mouseonthehill + 2 comments you also use "sum" and pass it the list.

def simpleArraySum(n, ar): return sum(ar)

amadoutidianeb1 + 0 comments i use this too

buciuser + 0 comments [deleted]

Shivamt949 + 0 comments through vector

adrianmoncar + 0 comments It's not a noob code ;) You are getting the real code experience, you will be better in a future.

gracieksg + 0 comments the simpleArraySum is supposed to have only ar in it as per the give . so how can it have parameter n

sonawaneomkar446 + 3 comments and I was saying to myself that if this is for beginners, I am gonna be Royally Screwed!!!

4t0m90 + 0 comments I tought the same!

greygrey3000 + 0 comments this is for beginners, like, really simple. You'll dream this stuff in no time if you practice

jym1999 + 0 comments hahahahaha

ErEllison + 3 comments This worked for me :

def simpleArraySum(n, ar): sum = 0 i = 0 while i < n : sum += ar[i] i += 1 return sum

programmer_ntn + 1 comment could you explain this code please?

apschauhan700 + 1 comment see full code here

https://github.com/akkshaychauhan/hacckerank-code/tree/master/Algorithms

viratc + 1 comment The link that you have provided seems to be broken!!

apschauhan700 + 0 comments i don't think so

msaravanan + 2 comments test case is failed if you give n=1000

shvmsxn41 + 0 comments Only If you do it by recursion. So better use loops.

cabaleirog + 0 comments Please

**be careful**with the variable names.**sum**is a Built-in function in Python.

lou13ee + 0 comments # feelsbadman

LisaWillCode + 3 comments No, before you do algorithm challenges, you should know the basics of a programming language. You need to know about functions and arrays for this challenge, even though it's just adding two numbers together.

By the way, you don't need to understand all that code they put in there. You only need to put your code where they tell you. But they ought to explain that, because it's very confusing to see all that.

doreenjeptoo + 0 comments Haha so true... im having a very hard time.

carloswm85 + 0 comments You're right, man.

ghazi261 + 0 comments I thought the "Write your code here" made it clear. You have a valid point, assuming they know the basics they should be able to read the comment as stated below and make sense out of it.

/* * Complete the simpleArraySum function below.

*/ static int simpleArraySum(int[] ar) { /** Write your code here. */

snaregurl + 0 comments Right just like i thought. I glad Im not alone lmao smh

shropshireclovis + 1 comment I think it's for beginners but there's just a lot in there. Like the "n" parameter for some reason is there but doesn't even have too be used. There's literally no point of it.

ddruva_boomer + 0 comments it can be used in other languages like c++.they dont have array.length function

vbhadoriya3 + 0 comments same bro

badepandu99 + 1 comment This is simple and gets the job done.

int sum=0,i,size,array[1000]; scanf("%d",&size); for(i=size;i>=0;i--) { scanf("%d",&array[i]); } for(i=size;i>=0;i--) { sum+=array[i]; } printf("%d",sum); return 0;

ddruva_boomer + 1 comment this is not javascript

carloswm85 + 0 comments I think it's C, not JS.

le171282 + 0 comments Here a sample from java static int simpleArraySum(int n, int[] ar) { int sum = 0; for (int i=0; i } return sum; }

jym1999 + 0 comments same for me!!!

[deleted] + 0 comments agree

cabaleirog + 0 comments [deleted]cabaleirog + 1 comment Don't let this frustrate you. Over time, your coding skills will improve, to the point that, this will become trivial to you :)

In an attempt to help new coders doing this challenge, I will add a few ways this problem could have been resolved; in addition, some comparisons among them.

***** Spoiler Alert

## Different approaches

Note that I removed the

**n**parameter. Dont see any use for it here, and**len(arr)**will provide the same value in constant time,**O(1)**.# Python comes with a Built-in function, sum, which # takes an iterable and returns the sum of its values. def array_sum_v1(arr): return sum(arr) def array_sum_v2(arr): total = 0 for number in arr: total += number return total def array_sum_v3(arr): total = 0 idx = len(arr) - 1 while idx >= 0: total += arr[idx] idx -= 1 return total # If you need to preserve `arr`, create an auxiliar # variable ``arr_cp`` and pop directly from that. def array_sum_v4a(arr): total = 0 # This is called slicing (can be used to copy the array) arr_cp = arr[:] # It will run until there are no more elements on arr_cp while arr_cp: # `pop` removes (and returns) the last element # We could use it directly, without the # variable assignment number = arr_cp.pop() total += number return total # We will remove `number = arr_cp.pop()` # and use it directly on the next line def array_sum_v4b(arr): total = 0 while arr: total += arr.pop() # Avoids one line return total # Overkill... # But just wanted to show that there are # much more ways to do this simple task; same as # for every non-trivial problem. # What is inside, its called a generator. def array_sum_v5(arr): return sum(x for x in arr)

## Time comparison

Below I created an array of 10000 random integers in the range [0, 10^9]. This will be used to compare among the functions.

import random random.seed(0) arr = [random.randint(0, 10**9) for _ in range(10**4)]

**Note**: Below code only works on a Jupyter Notebook.%timeit array_sum_v1(arr[:]) 1000 loops, best of 3: 334 Âµs per loop %timeit array_sum_v2(arr[:]) 1000 loops, best of 3: 543 Âµs per loop %timeit array_sum_v3(arr[:]) 1000 loops, best of 3: 1.38 ms per loop %timeit array_sum_v4a(arr) 1000 loops, best of 3: 1.55 ms per loop %timeit array_sum_v4b(arr[:]) 1000 loops, best of 3: 1.47 ms per loop %timeit array_sum_v5(arr[:]) 1000 loops, best of 3: 798 Âµs per loop

As expected, using the Built-in sum function is faster than looping over every item, loops in Python are kinda inefficient, but again, that is a topic for another day.

Hope this helps :)

jacob_cyrus_sta1 + 0 comments Very excellent explanation!

ashleyprimo + 0 comments def simpleArraySum(ar): return sum(ar)

That's it's, just the lines

`return sum(ar)`

don't overthink it some people get overwhelemd by the wealth of data in front of them. :)Chapagaingaurav1 + 0 comments i feel the same. i thought this would help to build some basics. It's way to beyond for starters like me.

mauryasushil22 + 0 comments yess,true.....

ashaysingh2017 + 0 comments what is the meaning of stray error 240 and 302 also what is the use of all the lengthy stuff given in the program originally..

monsterousopera1 + 5 comments They need to give you feedback for how these test cases work... Its like why didn't it pass test 2? also if they want it coded a specific way, why don't they tell you what way they want it rather then setting you losse then saying, "nope! thats not what I wanted. not goting to tell you why... just know that its worng..." I give up!

hard_system + 0 comments [deleted]khada404 + 0 comments int main() { int a[1000],n=1,i=0,result=0; scanf("%d",&n); for(i=0;i

`/* Enter your code here. Read input from STDIN. Print output to STDOUT */ return 0;`

}

zombiebot + 2 comments I'm having the same trouble. I've tested this locally and it works, and I've passed test case #0 and #1, but mysteriously, not #2 (apologies for the Pascal, I'm a Delphi developer and it's my most comfortable language):

(* Enter your code here. Read input from STDIN. Print output to STDOUT *) program ArraySum; var arraySize, i, sum, valErr: integer; intArray: array of integer; inputIntString, subIntString: string; begin readln(arraySize); SetLength(intArray, arraySize); readln(inputIntString); i := 0; while (i < arraySize) and (inputIntString <> '') do begin subIntString := Copy(inputIntString, 0, Pos(' ', inputIntString) -1); if subIntString = '' then begin subIntString := inputIntString; end; Val(subIntString, intArray[i], valErr); inputIntString := Copy(inputIntString, Pos(' ', inputIntString) + 1, Length(inputIntString)); i := i + 1; end; i := 0; sum := 0; while (i < arraySize) do begin sum := sum + intArray[i]; i := i+1; end; writeln(sum); end.

LMS11 + 0 comments No need to apologize. Pascal has proven to be one of the best languages for learning to code and IMHO it is perfectly ok here.

PS: I tested a completely different algorithm written in Pascal for this same exercise and it also failed the 3rd test case without any clue as to why. You have probably uncovered a bug/error in the test case specifically when run through the pascal compiler. I tried a "try/except" construct (guessing that the test failure might be due to a boundary condition) but this compiler implementation is gawing at the "try/except" construct itself and I haven't yet figured out why. If I find any repeatable means to confirm deny, I'll report.

PPS: using the same variable "i" in two different constructs that have completely different usages often causes pain. I'd choose a longer variable name. I'd also suggest using different names for different (obviously independant) variables based on their purpose/use.

Dan_meade + 0 comments [deleted]

b0kater + 1 comment You can download the testcases and verify yourself.

barry_keegan + 1 comment How?

redtigralj + 0 comments there is a link "Download sample test cases" in the right part of the screen.

sisokels + 0 comments I feel you, there should be a feedback mechanism for beginners. My code solve the Test case and then it fails two other cases and nothing else. How do I know what was wrong? I ask for help here and I dont get none

malakar_soham + 4 comments You can even do this without taking an array:

import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int sum=0; int n=sc.nextInt(); for(int i=0;i<n;i++) { sum = sum+(sc.nextInt()); } System.out.println(sum); } }

mbowen + 0 comments Memory savings!

vinod_vnsit + 0 comments [deleted]praritaxd + 0 comments nice one

arshnherlife + 0 comments import java.util.Scanner; public class Sumchallenge { public static void main(String args[]) { Scanner sc = new Scanner(System.in); int sum=0; //int n = sc.nextInt(); int count =1; for(int i =0;i<count;i++) { sum=sum+(sc.nextInt()); count++; if(count==7) { break; } } System.out.println(sum); } }

marinskiy + 1 comment Here is Python 3 solution from my HackerrankPractice repository:

n = int(input()) arr = list(map(int, input().split())) print(sum(arr))

Feel free to ask if you have any questions :)

cameronascanlan + 1 comment I did something similar with, but it's not passing any of the test cases.

`def sumOfList(): numberInList = input("Enter number of elements to be added: ") sumList = input("Enter numbers seperated by spaces: ") print(sum(list(map(int, sumList.split()))))`

marinskiy + 0 comments It's probably because you don't need these statements here: "Enter number of elements to be added: ", "Enter numbers seperated by spaces: "

daz1184 + 0 comments ## C# working example.

`static int simpleArraySum(int[] ar) { int total = 0; foreach (int n in ar) { total += n; } return total; }`

eandino + 3 comments Here is a simple solution I came up with.

`static int simpleArraySum(int n, int[] ar) { int sum = 0; for(int count = 0; count < ar.length; count++) { sum = sum + ar[count]; } return sum; }`

`Steps: 1.) You declare a variable to hold the sum. 2.) Give that variable an initial value. 3.) Now do a for loop to pass through every single element in the array. 4.) The first statement in the for loop sets an initial value to its variable count (can be named anything), int count = 0. The second piece of code (count < ar.length) sets a condition for which the loop will continue to run through the array, in this case, it will run until the end of the array. The third piece of code (count++) will add one to the counter which is the code that makes the counter pass through the array by increments of one (step by step). 5.) The code inside the brackets {sum = sum + ar[count]} will take the initial value of sum and add all of the values found inside the array to it. 6.) Finally the return statement will simply print out the new values of sum given by the for loop. *I hope this helps everyone, let me know if it does!`

sisokels + 0 comments This absolutely helped me solve this challenge! thanks a lot

sci5vm73lswn + 0 comments [deleted]inestsampaio + 0 comments Hi! How can you do this without initializing the array?

I tried your way but it keeps not working. So I tried

static int simpleArraySum(int[] ar) {

`int n = 1; int[] arrayFdp = new int [n]; int soma = 0; for (int i = 0; i < arrayFdp.Length; i++) { soma = soma + arrayFdp[i]; }`

return soma; }

`and it does't pass all the sample testcases! What am I doing wrong? Thanks`

usrahul436 + 2 comments int sum = 0; int i = 0; while (i < n){ sum += ar[i]; i += 1; } return sum;

bgseenivasababu + 0 comments int simpleArraySum(int n, int ar_size, int* ar) { int sum = 0; int i = 0; while (i < n) { sum += ar[i]; i += 1; } return sum;

}

int main() { int n; scanf("%i", &n); int *ar = malloc(sizeof(int) * n); for(int ar_i = 0; ar_i < n; ar_i++){ scanf("%i",&ar[ar_i]); } int result = simpleArraySum(n, n, ar); printf("%d\n", result); return 0; }

chalzromeo + 0 comments superb la

oriongalactic + 1 comment Today I recived the surprise that HackerRank finally is accepting JavaScript 6 (ES6)

ashishdalal_yes + 0 comments congrats

alexpap48 + 1 comment Can somebody answer me why this code is classified as wrong? It works perefct, I tested it with test data.

import java.io.

*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*;public class Solution {

`public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); //read array dimension int arr[] = new int[n];//make array with given dimension int sum = 0; String strSum = ""; for(int i=0; i < arr.length; i++){ arr[i] = in.nextInt(); sum = sum + arr[i]; if (i + 1 < arr.length ) { strSum = strSum + arr[i] + " + "; } else { strSum = strSum + arr[i]; } } strSum = strSum + " = " + sum; System.out.println(strSum); }`

}

sabareesh230593 + 1 comment how to solve this in php

sid28 + 1 comment For ultimate PHP cheese:

`return array_sum($ar);`

The standard built-in PHP functions make something like this rather a cake-walk. You can also of course do it with a loop.

kimberly2 + 2 comments My trouble is

`return "31";`

also passes. I can't seem to motivate myself to learn it right.

swap1712 + 0 comments Haha!

anirudh_rathore1 + 1 comment It will not pass when you submit the code :p As it checks two more cases.

Anusuyaece + 0 comments [deleted]

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