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Simple Array Sum
Simple Array Sum
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include
int main() { int n,sum=0; int i; scanf("%d",&n); int a[n];
{ printf("%d",sum); }
}
okay
TypeScript solution function simpleArraySum(ar: number[]): number { return ar.reduce((acc, val) => acc + val, 0); }
const input = require('fs').readFileSync(0, 'utf-8').split('\n'); const arr = input[1].split(' ').map(Number); console.log(simpleArraySum(arr));
int sum = 0; for (int i = 0; i < ar.Count; i++) { sum =sum+ ar[i]; } return sum; }