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If you dont mind me asking you, could you explain why you do this:
if(n==1){stringstr;cin>>str;stk.push(st);// why push the string onto the stack when its //empty? why not after (st+=str) cause then this would append to the string?st+=str;}
here we pushing the before appending a new one because when there will be a undo we can directly take the previous string from stack annd assign this value to
present string.
if(n==1)
{
st+=str;
stk.push(st);
}
else if(n==1)
{
st.erase(st.size()-k);
stk.push(st);
}
else if(n==4)
{
stk.pop();
st=stk.top();
}
just reversing the order of changing the string and pushing it on stack is giving segmentation fault in last few cases..please explain
@adi7tya & @badal_bokaro
if u add st in stk before the while it will work correctlly (means adding empty string in stack)
or
u can add in case 4;;=======
else if(x==4) { s.pop(); if(s.empty()) st="";
else {st=s.top();}}
i think u will understood the reason of segma. fault
in case 4 we should undo right..so inorder to do that we should push empty string..then we can add it to the string and make it when we need to undo..even i got the same doubt initially..once u pls trace it u will get that...
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If you dont mind me asking you, could you explain why you do this:
here we pushing the before appending a new one because when there will be a undo we can directly take the previous string from stack annd assign this value to present string.
hope it helps
Thanks! that makes sense.
if(n==1) { st+=str; stk.push(st); } else if(n==1) { st.erase(st.size()-k); stk.push(st); } else if(n==4) { stk.pop(); st=stk.top(); } just reversing the order of changing the string and pushing it on stack is giving segmentation fault in last few cases..please explain
same seg fault for me too
@adi7tya & @badal_bokaro if u add st in stk before the while it will work correctlly (means adding empty string in stack) or u can add in case 4;;======= else if(x==4) { s.pop(); if(s.empty()) st=""; else {st=s.top();}}
i think u will understood the reason of segma. fault
you just saved my day
but the string st is empty.why to push empty string in the stack?
in case 4 we should undo right..so inorder to do that we should push empty string..then we can add it to the string and make it when we need to undo..even i got the same doubt initially..once u pls trace it u will get that...
I think it should give atleast an error as you are inserting completely empty(Not even NULL) string in the stack.