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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Sales by Match
  5. Discussions

Sales by Match

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6052 Discussions

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  • quierountacopic1
     + 0 comments

    in c#

    int pairs = 0;
        var colors = ar.Distinct();
        foreach(var a in colors){
            var pair = ar.Where(x => x == a).ToList();
            if(pair.Count() % 2 != 0) pair.Remove(a);
            pairs += pair.Count()/2;
        }
        return pairs;

  • just_nick
     + 0 comments

    Python

    def sockMerchant(n, ar):
    seen = set()
    pairs = 0
    for c in ar:
        if c not in seen:
            seen.add(c)
        else:
            pairs +=1
            seen.remove(c)
    return pairs

  • Mukultyagi8387
     + 0 comments

    public static int sockMerchant(int n, List ar) { int pairCount = 0; Dictionary DictionaryObj = new Dictionary();

        foreach (var item in ar)
    {
        if (DictionaryObj.ContainsKey(item))
        {
            DictionaryObj[item]++;
        }
        else
        {
            DictionaryObj[item] = 1;
        }
    }

    foreach (int count in DictionaryObj.Values)
    {
        pairCount += count / 2;
    }
    return pairCount;
}****

  • dcruz14
     + 0 comments

    I want to recieve feedback about my solution in Javascript. How can I do it better?:

    function sockMerchant(n, ar) {
    ar.sort((a, b)=> a - b)
    let pairs=0;
    for(let i=0;i<ar.length;i++){
        if(ar[i]===ar[i+1]){
            pairs++;
            i++;
        }
    }
    return pairs;
}

  • zold_ithunter
     + 0 comments

    Java

    Map<Integer, Integer> check = new HashMap<>();
        AtomicInteger rs = new AtomicInteger(0);
        ar.forEach(it -> {
            if (check.containsKey(it)) {
                rs.getAndIncrement();
                check.remove(it);
            } else {
                check.put(it, it);
            }
        });
        return rs.get();