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  1. Prepare
  2. Data Structures
  3. Arrays
  4. Sparse Arrays
  5. Discussions

Sparse Arrays

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2432 Discussions

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  • danielsson_jacob
     + 0 comments

    My Java solution:

    public static List<Integer> matchingStrings(List<String> stringList, List<String> queries) {
        // Write your code here
        Map<String, Integer> stringCount = new HashMap<>();
        stringList.forEach(entry -> stringCount.compute(entry, (k, v) -> v == null ? 1 : v + 1));
        return queries.stream().map(query -> stringCount.getOrDefault(query, 0)).collect(Collectors.toList());
    }

  • sivaram_movva1
     + 0 comments

    c# linq, yield

    public static IEnumerable matchingStrings(List stringList, List queries) {
    foreach (var q in queries) { yield return stringList.Count(j=>j==q); } }

  • aminkhan84159
     + 0 comments

    Here's how we can do it in c#

    public static List matchingStrings(List stringList, List queries) { List totalCount = new List();

        foreach(var query in queries){
        int count = 0;
        for(int i = 0; i < stringList.Count; i++){
            if(query == stringList[i]){
                count++;
            }
        }
        totalCount.Add(count);
    }

    return totalCount;
}

  • wesleywchang
     + 0 comments

    Python: allocate extra space for linear runtime

    from collections import Counter

def matchingStrings(stringList, queries):
    # Write your code here
    counts = Counter(stringList)
    return [counts[query] for query in queries]

  • palashmondal351
     + 0 comments

    Python

    def matchingStrings(stringList, queries):
    return [stringList.count(each) if each in stringList else 0 for each in queries]