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I do not understand why in the 3rd pass is ans+=min(l[i - 1][1], l[i + 1][1])
and not the summatory of min
f.e in aaabaaa the possible ones aren't
aba
aabaa
aaabaaa
???
whith your code is only aaabaaa
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I do not understand why in the 3rd pass is ans+=min(l[i - 1][1], l[i + 1][1]) and not the summatory of min f.e in aaabaaa the possible ones aren't aba aabaa aaabaaa ??? whith your code is only aaabaaa