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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

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5141 Discussions

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  • niranjan77_wagh
     + 0 comments

    Using Rust

    fn staircase(n: i32) {
    for i in 0..n{
        for j in 1..n-i {
            print!{" "};
        }
        for j in n-i-1..n {
            print!{"#"};
        }
        println!();
    }
}

  • Paraschiv16
     + 0 comments

    my solution :

    public static void staircase(int n) {

    for(int i=1;i<=n;i++){
    //increment i at every loop (ex:first loop 6-1 = 5 spaces for the first '#')
    for(int j=1;j<=n-i;j++){ 
            System.out.print(" ");
    }

    //print #
    for(int k= 1;k<=i;k++){
         System.out.print("#");
    }

    //move to next line 
     System.out.println();
}

}

  • protik_1197
     + 0 comments

    python

    def staircase(n):
    for i in range(1, n+1):
        print(" "*(n-i) + "#"*i)

if __name__ == '__main__':
    n = int(input().strip())

    staircase(n)

  • adriancmiranda
     + 0 comments
    function staircase(n: number): void {
  let ctree = ""
  let step = 0;
  const total = n * n + n
  const mod = n + 1
  for (let id = 0; id < total; id++) { 
    const i = id % mod;
    const d = total - id;
    const f = d % mod;
    if (i === 0) {
      if (step) {
        ctree += "\n"
      }
      step++
    } else if (f > step) { 
      ctree += " "
    }  else {
      ctree += "#"
    }
  }
  console.info(ctree)
}

  • suongnguyenytm21
     + 0 comments

    KOTLIN

    fun staircase(n: Int): Unit {
    // Write your code here
    for (i in 0..<n) {
        var printSharp = n - i - 1
        for (j in 0..<n) {
            if (j >= printSharp) {
                print("#")
            } else {
                print(" ")
            }
        }
        println();
    }
}