Rust

fn staircase(n: i32) {
        for number in 1..=n {
            let line = "#".repeat(number as usize);  
            println!("{:>width$}", line, width = n as usize );
        };
}

public static void staircase(int n) { // Write your code here for(int i=0;i(n-2)) System.out.print("#"); else System.out.print(" ");

    }
    System.out.println();
}

}******

Starting from 0 will lead to a blank line, so start with 1. That's whart I was doing... lol

for i in range(1, n+1):
        print(' '*(n-i)+'#'*i)
				
	

** public static void staircase(int n) {

    for(int i=1;i<=n;i++)
    {
        for(int j=i;j<n;j++)
        {
           System.out.print(" ");
        }

        for(int j=i;j>=1;j--)
        {
           System.out.print("#");
        }

        System.out.println();

    }
}**

// Use Java version 15. + First, I realized that the "#" character should be printed from 1 up to n each line. + Therefore, the number of spaces printed on each line equals n minus the number of "#" characters. + To reduce the number of System.out.println calls (which improves I/O effiency) we can use the StringBuilder with the repeat() method (available since Java 11).

// Source Code: public static void staircase(int n) { // Write your code here StringBuilder sb = new StringBuilder(); for (int i = 0 ; i< n ; i++) {

    sb.append(" ".repeat(n-i-1))
    .append("#".repeat(i+1)).append("\n") ;
}

System.out.println(sb);




}