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  1. Prepare
  2. Python
  3. Closures and Decorators
  4. Standardize Mobile Number Using Decorators
  5. Discussions

Standardize Mobile Number Using Decorators

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229 Discussions

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  • karimsoft
     + 0 comments

    def wrapper(f): def fun(l): standardized = [] for number in l: num = number[-10:] standardized.append("+91 " + num[:5] + " " + num[5:])

        return f(standardized)
return fun

  • rjlharrylees
     + 0 comments
    def wrapper(f):
    def fun(l):
        sorted_l = sorted(int(i) for i in [x[-10:] for x in l])
        
        new = []
        for i in range(len(sorted_l)):
            new.append('+91 ' + str(sorted_l[i])[-10:-5] + ' ' + str(sorted_l[i])[-5:])
            print(new[i])
    return fun

  • Kuladeeppappu
     + 0 comments
    def wrapper(f):
    def fun(l):
        new = []
        for i in l:
            if len(i)==10:
                new.append("+91 " + i[0:5] + " " + i[5:10] )
            elif len(i)==11:
                new.append("+91 " + i[1:6] + " " + i[6:11])
            elif len(i)==12:
                new.append("+91 " + i[2:7] + " " + i[7:12])
            elif i[0:3]=="+91":
                new.append("+91 " + i[3:8] + " " + i[8:])
        f(new)
            
        # complete the function
    return fun

@wrapper
def sort_phone(l):
    print(*sorted(l), sep='\n')

if __name__ == '__main__':
    l = [input() for _ in range(int(input()))]
    sort_phone(l)

  • phamducctrung
     + 1 comment

    Python 3 solution

    def wrapper(f):
    def fun(l):
        format_f = [x[-10:] for x in l]
        decode_f = [f"+91 {x[0:5]} {x[5:10]}" for x in format_f]
        f(decode_f)
    return fun

@wrapper
def sort_phone(l):
    print(*sorted(l), sep='\n')

if __name__ == '__main__':
    l = [input() for _ in range(int(input()))]
    sort_phone(l)

  • unnatitank14
     + 0 comments
    def wrapper(f):
    def fun(l):
        new = []
        for i in l:
            new.append("+91 " + i[-10:-5] + " " + i[-5:])
            
        return f(new)
    return fun