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Standardize Mobile Number Using Decorators
Standardize Mobile Number Using Decorators
+ 0 comments lis = [(f"+91 {i[-10:-5]} {i[-5:]}") for i in sorted(l)] f(lis)
+ 0 comments Using f-strings:
def wrapper(f): def fun(l): formatted = [] for number in l: formatted.append(f"+91 {number[-10:-5]} {number[-5:]}") f(formatted) return fun
+ 0 comments def wrapper(f): def fun(l): nums = [] for i in l: temp = ['+91',i[-10:-5],i[-5:]] nums.append( " ".join(temp)) f(nums) return fun @wrapper def sort_phone(l): print(*sorted(l), sep='\n') if __name__ == '__main__': l = [input() for _ in range(int(input()))] sort_phone(l)
+ 0 comments import re def wrapper(f): def fun(l): pattern = re.compile(r'^(\+91|91|0){0,1}([\d]{5})([\d]{5})$') f([re.sub(pattern,r'+91 \2 \3',i) for i in l]) return fun
+ 0 comments My solution, I would like to know your opinion and if you could give me tips to improve I would be delighted!
def modify_number(number): number = number.replace('+', '') if len(number) == 12: number = f'+{number[:2]} {number[2:7]} {number[7:]}' elif len(number) == 11: number = f'+91 {number[1:6]} {number[6:]}' else: number = f'+91 {number[:5]} {number[5:]}' return number def wrapper(f): def fun(l): return f(map(modify_number, l)) return fun
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