Standardize Mobile Number Using Decorators

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229 Discussions

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  • + 0 comments

    Python 3 solution

    def wrapper(f):
        def fun(l):
            format_f = [x[-10:] for x in l]
            decode_f = [f"+91 {x[0:5]} {x[5:10]}" for x in format_f]
            f(decode_f)
        return fun
    
    @wrapper
    def sort_phone(l):
        print(*sorted(l), sep='\n')
    
    if __name__ == '__main__':
        l = [input() for _ in range(int(input()))]
        sort_phone(l) 
    
  • + 0 comments
    def wrapper(f):
        def fun(l):
            new = []
            for i in l:
                new.append("+91 " + i[-10:-5] + " " + i[-5:])
                
            return f(new)
        return fun
    
  • + 1 comment
    def wrapper(f):
        def fun(l):
            # complete the function
            new = []
            for number in l:
                num = number[-10:]
                new.append("+91 " + num[:5] + " " + num[-5:])
            return f(new)
        return fun
    
    @wrapper
    def sort_phone(l):
        print(*sorted(l), sep='\n')
    
    if __name__ == '__main__':
        l = [input() for _ in range(int(input()))]
        sort_phone(l) 
    
  • + 0 comments
    def wrapper(f):
        def fun(l):
            l = [f"+91 {num[-10:-5]} {num[-5:]}" for num in l]
            f(l)
        return fun
    
    @wrapper
    def sort_phone(l):
        print(*sorted(l), sep='\n')
    
    if __name__ == '__main__':
        l = [input() for _ in range(int(input()))]
        sort_phone(l) 
    
  • + 0 comments

    def wrapper(sort_fun):

    def fun(arg_l):
        # complete the function
        numeros = []
        for i in map(str, arg_l):
          recortar = i[-10:]
          num = f"+91 {recortar[:5]} {recortar[5:]}"
          numeros.append(num)
    
        return sort_fun(numeros)
    return fun