include

include

include

include

int main() { int a=0,b=0; float c=0,d=0; scanf("%d %d %f %f",&a,&b,&c,&d); printf("%d %d\n %.1f%.1f",a+b,a-b,c+d,c-d); }

    ***may ik why the test case are showing that this is wrong??******




return 0;

} `

include

include

include

include

Find the simplest code. Note we need to put a ".1" before %_f for rounding off. Ex - printf("%.1f", sumf)

int main() { int i1; int i2; float f1; float f2; int sum; int dif; float sumf; float diff; scanf("%d %d", &i1, &i2); scanf("%f %f", &f1, &f2); sum = i1+i2; dif = i1-i2; sumf= f1+f2; diff= f1-f2; printf("%d %d\n", sum, dif); printf("%.1f %.1f", sumf, diff);

return 0;

}

What's wrong in this code, outputs are same but its not correct. Can anyone help me.

**#include

include

include

include

int main() { int a,b; float c,d; printf(" "); scanf("%d %d",&a, &b);

printf(" ");
scanf("%f %f",&c,&d);

printf("\n %d",a+b);
printf(" %d",a-b);

printf("\n %.1f ",c+d);
printf(" %.1f",c-d);
return 0;

} **

include

include

include

include

int main() { int a ,b ; float c ,d ; scanf("%d%d",&a,&b); scanf("%f%f",&c,&d); int sum = a + b; printf("%d ",sum); int difference = a-b; printf("%d\n",difference); double k= c+d; double j = c-d; printf("%.1f ",k); printf("%.1f",j); return 0; }

how can I round off a float number to one decimal place ?