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  2. C
  3. Conditionals and Loops
  4. Sum of Digits of a Five Digit Number
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Sum of Digits of a Five Digit Number

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  • anubhav004
     + 0 comments

    int main() { int n, sum; scanf("%d", &n); while (n>0) { int temp = n%10; sum+=temp; n/=10; } printf("%d", sum); }

  • bhanuprakashsur3
     + 0 comments

    include

    include

    include

    include

    int main() {

    int n,j,sum=0;
scanf("%d", &n);
for (int i=0;i<n;){
    j = n%10;
    n = n/10;
    sum+=j;

}
printf("%d",sum);

return 0;

    }

  • yashdeora98294
     + 0 comments

    Here is Sum of digits of a five digit number solution in c - https://programmingoneonone.com/hackerrank-sum-of-digits-of-a-five-digit-number-solution-in-c.html

  • chaitanyahapse41
     + 0 comments

    include

    include

    include

    include

    int main() { int n; int sum = 0;

    scanf("%d", &n);

// Loop to calculate the sum of the five digits
for (int i = 0; i < 5; i++) {
    int remainder = n % 10;
    sum += remainder;
    n /= 10;
}

printf("%d\n", sum);
return 0;

    }

  • SVVBathini
     + 0 comments
    #include<stdio.h>

int main()
{
    int n;
    scanf("%d", &n);
    
    int sum=0;
    
    while(n > 0)
    {
        sum = sum + n % 10;
        
        n = n/10;
    }
    
    printf("%d", sum);
}