Or use + prefix to start counting from the begining:

head -n 22 | tail -n +12

head -22 | tail -11

I think this is the simplest way to do it.

I could come up with 3 solutions for this. Since most of us are in a learning phase, this may help in broadening the understanding of the language-

1. Remember "cut" for previous questions? You can change the delimiter to '\n', meaning that each field would now correspond to a line.

cut -d$'\n' -f12-22

2. Just like head, tail command exists which can print the last n lines of a file. So just pass the first 22 lines from head to tail via a pipe.

head -n 22 | tail -n 11

3. I actually came up with this solution first since I didn't know about tail. Basically, take the first 22 lines (from head) and pass then to a counter which will ignore the first 11 lines and start printing from the 12th.

count=1
head -n 22 | while read line; do if [ $count -ge 12 ]; then echo $line; fi; count=$(($count+1)); done

Hope it helps!

I found a simple solution using the sed command but I don't know if I can use it to solve this problem. Other approaches to find a solution consist in use both commands, head and tail, passing the output of the first command as input of the second command.