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2 approaches in C++
reusing existing sum of sub array
int birthday(vector<int> s, int d, int m) { if (s.size() < m) { return 0; } else { int sum {}; int count {}; for (int i=0; i<=s.size()-m; i++) { if (sum == 0) { for (int j=0; j<m; j++) { sum += s[j]; } } else { sum -= s[i-1]; sum += s[i-1+m]; } if (sum == d) count++; } return count; } }
brute force approach
int birthday(vector<int> s, int d, int m) { if (s.size() < m) { return 0; } else if (s.size() == m) { int sum = 0; for (int i : s) { sum += i; } return d == sum; } else { int count {}; for (int j = 0; j <= s.size()-m; j++) { int sum {}; for (int i = j; i < j+m; i++) { sum += s[i]; } if (sum == d) count ++; } return count; } }
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Subarray Division
You are viewing a single comment's thread. Return to all comments →
2 approaches in C++
reusing existing sum of sub array
brute force approach