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    select c.company_code, c.founder, count(distinct(e.lead_manager_code)) as total_lead_managers, count(distinct(e.senior_manager_code)) as total_senior_managers, count(distinct(e.manager_code)) as total_managers, count(distinct(e.employee_code)) as total_employees from company c join employee e on e.company_code = c.company_code group by c.company_code, c.founder order by c.company_code