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    SELECT c.company_code, c.founder, (SELECT COUNT(DISTINCT lead_manager_code) FROM lead_manager AS l WHERE l.company_code = c.company_code ), (SELECT COUNT(DISTINCT senior_manager_code) FROM senior_manager AS s WHERE s.company_code = c.company_code ), (SELECT COUNT(DISTINCT manager_code) FROM manager AS m WHERE m.company_code = c.company_code ), (SELECT COUNT(DISTINCT employee_code) FROM employee AS e WHERE e.company_code = c.company_code ) FROM company AS c ORDER BY c.company_code ASC;