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select c.company_code, c.founder, count(distinct(e.lead_manager_code)), count(distinct(e.senior_manager_code)),
count(distinct(e.manager_code)), count(distinct(e.employee_code)) from company c
join employee e
on c.company_code = e.company_code
group by c.company_code, c.founder
order by c.company_code asc;
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select c.company_code, c.founder, count(distinct(e.lead_manager_code)), count(distinct(e.senior_manager_code)), count(distinct(e.manager_code)), count(distinct(e.employee_code)) from company c join employee e on c.company_code = e.company_code group by c.company_code, c.founder order by c.company_code asc;