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Fixed version
select c.company_code, c.founder, count(distinct e.lead_manager_code), count(distinct e.senior_manager_code), count(distinct e.manager_code), count(distinct e.employee_code) from company c inner join employee e on e.company_code = c.company_code group by c.company_code,c.founder order by c.company_code;
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New Companies
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Fixed version