We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. SQL
  3. Advanced Select
  4. The PADS
  5. Discussions

The PADS

Sort by

recency

|

5525 Discussions

|

  • vb_gupta
     + 0 comments

    SELECT CONCAT(O.Name,'(',LEFT(O.Occupation, 1),')') FROM OCCUPATIONS AS O ORDER BY O.NAME ASC;

    SELECT CONCAT ('There are a total of ', COUNT(*),' ',LOWER(O.Occupation),'s.') AS SUMMARY FROM OCCUPATIONS AS O GROUP BY O.Occupation ORDER BY SUMMARY ASC

  • pratikbawane101
     + 0 comments

    select Name||'('|| substr(Occupation,1, 1) ||')' from OCCUPATIONS;

    select 'There are a total of ' || count(Occupation) ||' ' || lower(Occupation) || 's.' from OCCUPATIONS group by Occupation order by count(Occupation), case lower(Occupation) when 'doctor' then 1 when 'singer' then 2 when 'actor' then 3 when 'professor' then 4 end;

  • rajeevrawat727
     + 0 comments

    SELECT CONCAT(Name,"(",LEFT(Occupation,1),")") FROM OCCUPATIONS ORDER BY Name ASC; SELECT CONCAT("There are a total of ",COUNT(Name)," ",lower(Occupation),"s.") FROM OCCUPATIONS GROUP BY Occupation Order By COUNT(Name) ASC, lower(Occupation) ASC;

  • elangojagan2000
     + 0 comments

    SELECT CONCAT(Name,"(",LEFT(Occupation,1),")") FROM OCCUPATIONS ORDER BY Name ASC; SELECT CONCAT("There are a total of ", count(OCCUPATION), " ", LOWER(OCCUPATION), "s.") FROM OCCUPATIONS GROUP BY OCCUPATION ORDER BY COUNT(OCCUPATION) ASC;

  • roshantomar9713
     + 1 comment

    MySQL Solution

    select concat(name,'(',left(occupation,1),')') from occupations order by name;

    select concat('There are a total of ',count(occupation),' ',lower(occupation),'s','.') from occupations group by occupation order by count(occupation),occupation ;