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  1. Left Rotation
  2. Discussions

Left Rotation

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153 Discussions

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  • harrydunn333
     + 0 comments
    def rotateLeft(d, arr):
    for i in range(d):
        arr.append(arr.pop(0))
    return arr

  • chreachhunneng
     + 0 comments

    I think this solution only few line in java

        public static List<Integer> rotateLeft(int d, List<Integer> arr) {
        for(int i=0; i < d; i++){
            arr.add(arr.remove(0));
        }
        return arr;
    }

  • mohapatra_shrey1
     + 0 comments

    Python Solution with minimum no of rotations remainder = minimum no. of rotations or swaps required on the arr

    def rotateLeft(d, arr):
    n=len(arr)
    rem=d%n
    if d==0 or rem==0:
        return arr
    else:
        for i in range(rem):
            arr.append(float('-inf'))
            arr[0],arr[-1]=arr[-1],arr[0]
            arr.pop(0)
        return arr

  • vinayak25nair
     + 0 comments

    Java Easy solution

    public static List<Integer> rotateLeft(int d, List<Integer> arr) {

    if(d==arr.size()){
        return arr;
    }
    int i=0;
    for(;i<d;d--){
        int temp = arr.get(i);
        arr.remove(i);
        arr.add(temp);
    }
    return arr;
}

  • victor_barrios_1
     + 0 comments

    Swift solution:

    func rotateLeft(d: Int, arr: [Int]) -> [Int] {
    let n = arr.count
    
    // 'mod' operation avoids unnecessary rotations
    let rotations = d % n
    
    return Array(arr[rotations...] + arr[..<rotations])
}