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  1. The Full Counting Sort
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The Full Counting Sort

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82 Discussions

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  • pradymm
     + 0 comments
    public static void countSort(List<List<String>> arr) {
// Write your code here
List<List<String>> buckets = new ArrayList<>();
for(int i =0; i < 100; i++){
    buckets.add(new ArrayList<>());
}
int n= arr.size();
for(int i =0; i < n ; i++){
    Integer key = Integer.parseInt(arr.get(i).get(0));
    String str = arr.get(i).get(1);
    if(i < n /2){
        str = "-";
    }
    buckets.get(key).add(str);
}
StringBuilder sb = new StringBuilder();
for(List<String> bucket : buckets){
    for(String s : bucket){
        sb.append(s).append(" ");
    }
}
System.out.println(sb.toString());
}

  • benjuniour26
     + 0 comments

    Python solution:

    def countSort(arr):
    mid_point = len(arr)//2
    mid_point_arr = [[elem[0], "-"] for elem in arr[:mid_point]]
    dashed_arr = mid_point_arr + arr[mid_point:]
    dashed_arr.sort(key=lambda elem: int(elem[0]))
    [print(elem[1], end=" ") for elem in dashed_arr]

  • victor_reial
     + 0 comments

    Rust best solution

    If you’re looking for solutions to the 3-month preparation kit in either Python or Rust, you can find them below: my solutions 

    fn full_countint_sort(arr: &[Vec<String>]) {
    //Time complexity: O(n)
    //Space complexity (ignoring input): O(1)
    let mut sorted_array: Vec<String> = vec!["".to_string(); 101];
    for index in 0..arr.len() {
        let sorted_index = arr[index][0]
            .parse::<usize>()
            .expect("To be able to parse correctly");
        if index < arr.len() / 2 {
            sorted_array[sorted_index].push_str(" -");
        } else {
            sorted_array[sorted_index].push(' ');
            sorted_array[sorted_index].push_str(&arr[index][1]);
        }
    }
    let mut result_array = String::new();
    for string in sorted_array {
        if !string.is_empty() {
            if result_array.is_empty() {
                result_array = string[1..].to_string();
            } else {
                result_array.push_str(&string);
            }
        }
    }
    println!("{}", result_array);
}

  • victor_reial
     + 0 comments

    Python best solution

    If you’re looking for solutions to the 3-month preparation kit in either Python or Rust, you can find them below: my solutions 

    def full_counting_sort(arr):
    #Time complexity: O(n)
    #Space complexity (ignoring input): O(1)
    sorted_array = [""]*101
    for index in range(0, len(arr)):
        sorted_index = int(arr[index][0])
        if index < len(arr)/2:
            sorted_array[sorted_index] += " -"
        else:
            sorted_array[sorted_index] += " "
            for letter in arr[index][1]:
                sorted_array[sorted_index] += letter

    result_string = ""
    for string in sorted_array:
        result_string += string

    print(result_string[1:])

  • michael_chen_0
     + 0 comments

    Python 3 solution:

    def countSort(arr: list[list[str]]) -> None:
    for i in range(len(arr) // 2):
        arr[i][1] = "-"
    arr.sort(key=lambda x: int(x[0]))
    print(*(x[1] for x in arr))