We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Lonely Integer
  2. Discussions

Lonely Integer

  • geyoga
     + 0 comments

    here is my solution using dictionary with Swift

    func lonelyinteger(a: [Int]) -> Int {
    // Write your code here
    var dict: [Int: Int] = [:]
    // create Dictionary based on array that we have
    for number in a {
        // check that number is in Dictionary
        if dict.contains(where: {$0.key == number}) {
            // add counter when already in it
            dict[number]! += 1
        } else {
            // initiate new number
            dict[number] = 1
        }
    }
    // get first dictionary where it has only one value
    if let aloneNumber = dict.first(where: {$0.value == 1}) {
        return aloneNumber.key
    }
    return 0
}