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  1. Mini-Max Sum
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Mini-Max Sum

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279 Discussions

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  • fernandoituarte1
     + 0 comments
    const { sum, min, max } = arr.reduce((acc, curr) => {
        acc.sum += curr;
        acc.min = curr < acc.min ? curr : acc.min;
        acc.max = curr > acc.max ? curr : acc.max;
        return acc;
    },
    {
        sum: 0,
        min: Infinity,
        max: -Infinity,
    })
    console.log(sum - max, sum - min)

  • caribe_007
     + 0 comments
    • from functools import reduce
    • min_sum = reduce(lambda x,y: x+y, sorted(arr, reverse=True)[1:])
    • max_sum = reduce(lambda x,y: x+y, sorted(arr)[1:])
    • print(min_sum, max_sum)

  • myclg7
     + 0 comments
    function miniMaxSum(arr) {
    let sum=0,min=arr[0],max=arr[0];
    for(let i=0; i<arr.length; i++){
        sum = sum + arr[i];
        if(arr[i]<min){
            min=arr[i];
        }
        if(arr[i]>max){
            max=arr[i];
        }
    }
    console.log(sum-max,sum-min)
}

  • versona0450
     + 0 comments

    //node code

    function miniMaxSum(arr) {
    // Write your code here
    let result = [0, 0];
    let sort = arr.sort((x,y) => x-y)
    
    sort.forEach((val, i) => {
        if(i == 0){
            result[1] += sort.filter((_, index) => index !== i)
                .reduce((idx, val) => idx + val, 0);
        }else if(i == sort.length - 1){
            result[0] += sort.filter((_, index) => index !== i)
                .reduce((idx, val) => idx + val, 0);
        }
    })
    console.log(result[0], result[1])
}

  • sureshvasu258
     + 0 comments

    // java code

    int min = Integer.MAX_VALUE; int max = Integer.MIN_VALUE; long sum = 0;

       for (int x : arr){
       sum += x;
      if (x < min)
         min = x;
    }
     for (int x : arr){
        if (x > max)
            max = x;
    }

    long minSum = sum - max;
    long maxSum = sum - min;

    System.out.print(minSum +" " + maxSum);

}

    }