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  1. Sum vs XOR
  2. Discussions

Sum vs XOR

  • nandakishore03
     + 0 comments

    My Solution in java8: 

    public static long sumXor(long n) {
// Write your code here
Long res = 0L, nn = n;
res = (long)Math.pow(2,(Long.toBinaryString(nn).chars().filter(x -> x == '0').count()));
return n == 0 ? 1 : res;
}