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P2 chooses the 2nd index! (k=2)
index squared (k²) is therefore (k² = 2² = 4)
The confusing bit is, that P1 has to pay P2 the costs of the index squared, not the cost of the height of the tower at that index!
So you'd better put all those big towers on low indices ;)
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Tower Breakers - The Final Battle
You are viewing a single comment's thread. Return to all comments →
P2 chooses the 2nd index! (k=2)
index squared (k²) is therefore (k² = 2² = 4)
The confusing bit is, that P1 has to pay P2 the costs of the index squared, not the cost of the height of the tower at that index!
So you'd better put all those big towers on low indices ;)