Discussion on Tree: Huffman Decoding Challenge

seshu_thota 2 years ago+ 1 comment

what does the "temp = root " does here in the end

if temp.right==None and temp.left==None:
            string.append(temp.data)
            temp=root  <---this one
    b=''.join(string)
    print b

davebrophy 2 years ago+ 1 comment

Not my code but I did something similar.

Root is stored and never changes, so you can go back there after you reach a leaf. The variable "temp" stores the current position as you traverse down towards a leaf.

Once you reach a leaf, identified by the lack of left/right links, you retrieve the data and add it to your string. Then you need to reset your position to the root node, so you set temp=root.

timnosov 2 years ago+ 1 comment

temp here is obviously a poor variable name choice. The variable head should be left untouched and a new variable, forexample current_node or just node should be used to traverse the tree down.

def is_last(node):
    return not node.left and not node.right

def go_right(node):
    return node.right

def go_left(node):
    return node.left

# Enter your code here. Read input from STDIN. Print output to STDOUT
def decodeHuff(root , s):
    result = []
    node = root
    for char in s:
        if char == '1':
            node = go_right(node)
        elif char == '0':
            node = go_left(node)
        
        if is_last(node):
            result.append(node.data)
            node = root
            
    print ''.join(result)

uds5501 12 months ago+ 1 comment

I don't see how exactly your solution is different. Additionaly, temp has a local scope and leaves the root un bothered in the original solution. I can't really see how your solution improved the former

gelmilorenzo 3 days ago+ 0 comments

I know this is old but... Python is all about clarity (arguably, all languages should be, but python in particular). We might discuss about the need to create functions just to move along the tree, but variable names are not something that can just be overlooked.