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The 9, 10, and 11 nodes are all to the right of the 1 node. If the 1 node had a left child, 12, it's right child would be 13, not 10. You have to expand the tree horizontally for each additional level the tree.
Tree : Top View
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Will this solution work for the below input?
I guess "11" will not be printed in spite of it being visible, as the branch containing 9 will not be traversed?
The 9, 10, and 11 nodes are all to the right of the 1 node. If the 1 node had a left child, 12, it's right child would be 13, not 10. You have to expand the tree horizontally for each additional level the tree.
Your example is not a binary tree. void top_view_dir(node *root, int dir) { if(root != NULL) { if(dir) { top_view_dir(root->left, 1); printf("%d ", root->data); } else { printf("%d ", root->data); top_view_dir(root->right, 0); } } } void top_view(node * root) { if(root == NULL) { return; } else { top_view_dir(root->left, 1); printf("%d ", root->data); top_view_dir(root->right, 0); } }
Exactly. I am looking for a perfect soluction for this problem.