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  1. Prepare
  2. Algorithms
  3. Strings
  4. Two Strings
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Two Strings

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2301 Discussions

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  • marcelojvaldez_1
     + 0 comments

    Python3:

    def twoStrings(s1, s2):
    s1_set= set(s1)
    s2_set= set(s2)
    if s1_set.intersection(s2_set) == set():
        return "NO"
    else:
        return "YES"

    More concise: 

    def twoStrings(s1, s2):
	return "YES" if set(s1) & set(s2) else "NO"

  • nice00guy69
     + 0 comments
        # s1 = set(s1)
    # s2 = set(s2)
    
    # for i in s1:
    #     for j in s2:
    #         if i == j:
    #             return "YES"
    # return "NO"
    return "YES" if set(s1) & set(s2) else "NO"

  • pnsemonov
     + 0 comments

    JS

    const twoStrings = (string1, string2) => new Set(string1).intersection(new Set(string2)).size ? 'YES' : 'NO';

  • weaslypaul923
     + 0 comments

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  • whiland
     + 0 comments

    My minimaist O(n + m) solution:

        public static String twoStrings(String s1, String s2) {
    boolean[] s1_array = new boolean[26];
    int base = (int)'a';
    
    for (int i = 0 ; i < s1.length() ; i++){
        int position = (int)s1.charAt(i) - base;
        
        s1_array[position] = true;
    }
    
    for (int i = 0 ; i < s2.length() ; i++){
        int position = (int)s2.charAt(i) - base;
        
        if (s1_array[position] == true) return "YES";
    }
    
    return "NO";
    }