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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Validating phone numbers
  5. Discussions

Validating phone numbers

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487 Discussions

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  • lsloan
     + 0 comments

    Strange to see such a simple challenge following a few that are more complex. I'm used to challenges being increasingly more complex.

    import re, sys

print('\n'.join(
  ['NO', 'YES']
  [re.match(r'^[789]\d{9}$', l) is not None]
  for l in sys.stdin.readlines()[1:]))

  • teja270803
     + 0 comments

    n = int(input()) # Read number of test cases

    for i in range(n):

    ph_no = input()  # Read each mobile number

if len(ph_no) == 10 and ph_no[0] in ['7', '8', '9'] and ph_no.isdigit():
    print("YES")
else:
    print("NO")

  • DixieSturgeon5
     + 1 comment

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  • Navanil_Ghosh
     + 1 comment

    n=int(input()) for i in range(n): s=input() a='YES' if len(s)!=10 or s[0] not in '789': a="NO" if any(not j.isdigit() for j in s): a="NO" print(a)

  • sharmaj1
     + 0 comments
    #import regex package --> iterate through input, use regex "^[789]\d{9}$" to match to input using findall --> finall returns a list, if list size is not 0 then a match has been found, and print according result

import re

for i in range(int(input())):
    num = input()
    x = re.findall("^[789]\d{9}$", num)
    
    if len(x) > 0:
        print("YES")
    else:
        print("NO")