Discussion on Validating phone numbers Challenge

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12 hours ago+ 0 comments

import re

N = int(input())

for _ in range(N):
    print("YES") if re.search(r"^[789]\d{9}$", input()) else print("NO")

19 hours ago+ 0 comments

import re n = int(input()) number_list = []

for i in range(n): temp_list = [] for x in range(10): num = int(input()) temp_list.append(num) number_list.append(temp_list)

joined_list = [''.join(map(str, inner_list)) for inner_list in number_list]

for item in joined_list: if re.search('(^(9|8|7)\d{9}$)', item): print('YES') else: print('NO')

3 days ago+ 0 comments

import re
n = input()
if re.search(r"^(7|8|9)\d{9}$",n):
     print("Yes")
else:
     print("No")

3 days ago+ 0 comments

import re def checker(pn): pat=r"[789]\d{9}$" if re.match(pat,pn): return("YES") else: return ("NO")

n=int(input()) for i in range(n):

print(checker(input()))

2 weeks ago+ 0 comments

Here i build this problem logic without RegEx Module Use following code

n=int(input())
lista=[]
for i in range(n):
    number=input()
    lista.append(number)

for item in lista:
    a=item[0]
    if(len(item)==10):
        if( (a=='9') or (a=='8') or (a=='7')):
            try:
                no=int(item)
                print('YES')
            except:
                print('NO')
        else:
            print('NO')
    else:
        print('NO')

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