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Weather Observation Station 19
Weather Observation Station 19
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SQL Server Solution
After a lot of searching, I finally found the answer, because I had no idea that the Euclidean distance was the standard way to measure distance. Later, I got it and understood everything.
SET @min_lat_n = (SELECT MIN(lat_n) FROM station); set @min_long_w = (select min(long_w) from station); set @Max_lat_n = (select max(lat_n) from station); set @max_long_w = (select max(long_w) from station);
select round(sqrt(pow(@Max_lat_n - @min_lat_n, 2) + pow(@max_long_w - @min_long_w, 2)), 4) from station limit 1;
select round(sqrt(power(max(LAT_N)-min(LAT_N),2)+pow(max(LONG_W)-min(LONG_W),2)),4) from station; /* d≈ (Δx)^ 2+(Δy)^ 2
SELECT ROUND(SQRT(POWER(MAX(LAT_N)-MIN(LAT_N),2)+ POWER(MAX(LONG_W)-MIN(LONG_W),2)),4) FROM STATION
This code worked for me because if I am not using decimal it's taking value till multiple place and round is not working properly