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  1. Prepare
  2. SQL
  3. Basic Select
  4. Weather Observation Station 4
  5. Discussions

Weather Observation Station 4

  • ujjujais17
     + 0 comments

    There are two way to solve that problem;

    1. SELECT COUNT(city)-COUNT(DISTINCT(city) FROM Station;

    2. SELECT COUNT(city)-COUNT(DISTINCT(city) AS Difference FROM Station;