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  1. Prepare
  2. SQL
  3. Basic Select
  4. Weather Observation Station 5
  5. Discussions

Weather Observation Station 5

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7261 Discussions

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  • dustin_binge
     + 0 comments
    select
city,
char_length(city)
from STATION
where city =
    (select
        city
    from STATION
    where char_length(city) = 
        (select min(char_length(city))
        from STATION order by city)
    order by city
    limit 1)
or city =
    (select
        city
    from STATION
    where char_length(city) = 
        (select max(char_length(city))
        from STATION order by city)
    order by city
    limit 1);

  • amandacaravieri1
     + 0 comments

    with base as ( select city, LENGTH(city) as size, row_number() over (partition by LENGTH(city) order by city) as row_id
    from station where LENGTH(city) = (select max(LENGTH(city)) from station) or LENGTH(city) = (select min(LENGTH(city)) from station) order by LENGTH(city) desc, city asc ) select city,size from base where row_id=1

  • 243rushabh
     + 0 comments
    (
    SELECT CITY, LENGTH(CITY) AS city_length 
    FROM STATION 
    ORDER BY city_length, CITY ASC
    LIMIT 1
)
UNION
(
    SELECT CITY, LENGTH(CITY) AS city_length 
    FROM STATION 
    ORDER BY city_length DESC, CITY ASC 
    LIMIT 1
)

  • mufadluqman
     + 0 comments
    (
  SELECT CITY, CHAR_LENGTH(CITY) AS NAME_LENGTH
  FROM STATION
  WHERE CHAR_LENGTH(CITY) = (
      SELECT MIN(CHAR_LENGTH(CITY)) FROM STATION
  )
  ORDER BY CITY
  LIMIT 1
)
UNION ALL
(
  SELECT CITY, CHAR_LENGTH(CITY) AS NAME_LENGTH
  FROM STATION
  WHERE CHAR_LENGTH(CITY) = (
      SELECT MAX(CHAR_LENGTH(CITY)) FROM STATION
  )
  ORDER BY CITY
  LIMIT 1
);

  • rajatsinghnayal
     + 0 comments

    -- City with the shortest name SELECT TOP 1 CITY, LEN(CITY) AS NAME_LENGTH FROM STATION ORDER BY LEN(CITY), CITY;

    -- City with the longest name SELECT TOP 1 CITY, LEN(CITY) AS NAME_LENGTH FROM STATION ORDER BY LEN(CITY) DESC, CITY;