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  1. Prepare
  2. Python
  3. Collections
  4. Word Order
  5. Discussions

Word Order

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1650 Discussions

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  • Reshmafredy999
     + 0 comments
    # Enter your code here. Read input from STDIN. Print output to STDOUT
from collections import Counter
if __name__ == '__main__':
    n  = int(input())
    words = []
    for _ in range(n):
        s = input()
        words.append(s)
        
    total = 0
    count = Counter(words)
    print(len(count))
    for item in count:
        print(count[item], end=" ")

  • sripavanvannam
     + 0 comments

    n=int(input())

    k={} list1=[]

    for i in range(n): stri=input() list1.append(stri)

    for i in list1: k[i]=k.get(i,0)+1 print(len(k)) for i ,p in k.items(): print(p,end=" ")

  • alex_dremer93
     + 0 comments
    n = int(input())
word_count = {}
order = []
for _ in range(n):
    word = input().strip()
    if word not in word_count:
        word_count[word] = 0
        order.append(word)
    word_count[word] += 1
print(len(order))
print(' '.join(str(word_count[word]) for word in order))

  • 191FA07033
     + 0 comments
    from collections import Counter,OrderedDict
n=int(input())
a=[input() for _ in range(n)]
c=list(OrderedDict.fromkeys(a))
d=Counter(a)
b=[d[_] for _ in c]
print(len(b))
print(*b,end=" ")

  • shihamfm
     + 0 comments

    from collections import Counter

    n = int(input().strip()) words = [input().strip() for _ in range(n)]

    words_count = Counter(words)

    distinct = [] for w in words: if w not in distinct: distinct.append(w)

    print(len(distinct))

    for d in distinct: print(words_count[d], end=" ") print()