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  2. Python
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  4. Word Order
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Word Order

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1632 Discussions

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  • shruti_kapse06
     + 0 comments
    from collections import OrderedDict

n = int(input())
count = 0
inp_dict = OrderedDict()

for i in range(n):
    word = str(input())
    
    if word in inp_dict:
       inp_dict[word] += 1
    else:
        inp_dict[word] = 1
        count +=1
        
print(count)
print(*(inp_dict[word] for word in inp_dict))

  • rp3326
     + 0 comments

    from collections import Counter n =int(input()) li=[]

    for i in range(n): word=input() li.append(word)

    count_words=len(set(li)) print(count_words)

    counts = Counter(li)

    for count in counts.values(): print(count,end=" ")

  • ambujtiwarisidhi
     + 0 comments

    n = int(input())

    dic = {}

    for _ in range(n): word = input() if word in dic.keys(): dic[word]+=1 else: dic[word] = 1

    print(len(dic.keys()))

    occ = [str(i) for i in dic.values()]

    print(' '.join(occ))

  • yashdeora98294
     + 0 comments

    Here is HackerRank Word Order in python solution - https://programmingoneonone.com/hackerrank-word-order-problem-solution-in-python.html

  • deskonly69
     + 0 comments

    n = int(input()) words = {}

    for i in range(n): word = input() words[word] = words.get(word,0) + 1 print(len(words)) for vale in words.values(): print(vale,end=" ")