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  1. Prepare
  2. Python
  3. Collections
  4. Word Order
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Word Order

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1612 Discussions

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  • akid_harith_sc21
     + 0 comments

    Dont crtl c/v ! Read and pls try to comprehend

    n = int(input()) # Number of words l = [] # List to store the words seen = {} # Dictionary to keep track of occurrences

    for i in range(n): word = input() # Input the word l.append(word) # Append word to list if word in seen: seen[word] += 1 # Increment count if word is already in the dictionary else: seen[word] = 1 # Initialize count to 1 if it's the first occurrence of the word

    result = [] for word in l: if seen.get(word) is not None: result.append(seen[word]) # Append the count of occurrences del seen[word] # Remove the word from the dictionary to avoid duplicates in output

    print(len(result)) # Print the number of distinct words print(*result) # Print the counts of occurrences in the order of appearance

  • USM2019100130
     + 0 comments

    from collections import defaultdict

    dic=defaultdict(int)

    for i in range(int(input())):

    dic[input()]+=1

    print(len(dic))

    print(' '.join([ str(dic[x]) for x in dic.keys() ]))

  • Awaish7
     + 0 comments
    def distinct(words: list[str]) -> None:
    counter: dict[str,int] = {}

    for word in words:
        if word in counter:
            counter[word] += 1
        else:
            counter[word] = 1

    print(len(counter))
    for v in counter.values():
        print(v, end=' ')


if __name__ == "__main__":
    n = int(input())
    words = [input() for i in range(n)]
    distinct(words)

  • dlesov
     + 0 comments
    from collections import OrderedDict

od = OrderedDict()
for _ in range(int(input())):
    key = input()
    od[key] = od.get(key, 0) + 1
print(len(od))
print(" ".join(map(str, od.values())))

  • singhshrajan
     + 0 comments
    1. using default dict
    2. from collections import defaultdict
    3. n =int(input())
    4. li = []
    5. my_dict = defaultdict(int)
    6. for i in range (n):
    7. i = input()
    8. li.append(i)
    9. for i in li:
    10. my_dict[i] +=1
    11. print(len(my_dict)) print(" ".join(map(str,my_dict.values())))