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  2. Python
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  4. Words Score
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Words Score

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  • frankiepang2010
     + 0 comments

    for python 3, the issue is in the line for (++score). It doesn't add 1.

    It's a operators increment and decrement value of a variable by 1 works for C and Java. But these operators won't work in Python.

    To debug, change it from (++score) => (score += 1)

  • sanjeevi_krishn
     + 0 comments
    def score_words(words):
    a = ['a', 'e', 'i', 'o', 'u','y']
    b = []
    for i in words:
        c = 0
        for j in i:
            if j in a:
                c += 1
        if c %2 == 0:
            b.append(2)
        else:
            b.append(1)
    return sum(b)

  • dharshan94880_b1
     + 0 comments
    def score_words(words: list[str]) -> int:
    """Score words based on how many vowels in a word."""
    score = 0
    for word in words:
        even = True
        for letter in word:
            if letter in {'a', 'e', 'i', 'o', 'u', 'y'}:
                even = not even
        score += 2 if even else 1
    return score

  • sakshemgotekar2
     + 0 comments

    n = int(input()) user_input = input().split()

    def score_words(ui): vowels = ['a','e','i','o','u','y'] count = 0 list1 = [] for i in ui: temp_alpha = list(i) for j in range(len(temp_alpha)): if temp_alpha[j] in vowels: count += 1 if count % 2 ==0: list1.append(2) count = 0 else: list1.append(1) count = 0 return sum(list1) print(score_words(user_input))

  • enkidupal
     + 0 comments
    # Enter your code here. Read input from STDIN. Print output to STDOUT
from typing import Sequence

vowels = set('aeiouy')

def is_vowel(c):
    return c in vowels

def score_word(word: str) -> int: 
    return 2 if sum(is_vowel(c) for c in word) % 2 == 0 else 1
    
def score_words(words: Sequence[str]) -> int:
    return sum(score_word(word) for word in words)


n = int(input())
words = input().split(" ")


#print(n)
#print(word)

print(score_words(words))
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