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Words Score

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164 Discussions

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  • CSE23_0101628
     + 0 comments

    import re

    def score_words(words): pattern = re.compile(r'[aeiouy]') sum1=0 for i in words.split(): if len(pattern.findall(i))%2==0: sum1 +=2 else: sum1 +=1 return(sum1) if name == "main": n = int(input()) word = input() print(score_words(word))

  • yashdeora98294
     + 0 comments

    Here is HackerRank Words Score in Python solution - https://programmingoneonone.com/hackerrank-words-score-problem-solution-in-python.html

  • luca_h94
     + 1 comment
    i, words = input(), input()

def score_words(words):
    vowels=["a","e","i","o","u","y"]
    words = words.split()
    score = 0
    for word in words:
        vowelcount = 0
        for char in word:
            if char in vowels:
                vowelcount +=1
        if vowelcount % 2 == 0:
            score += 2
        else:
            score += 1 
    print(score)

score_words(words)

  • arohi_agrawal111
     + 0 comments

    Just the ++score has to be converted into score += 1. Rest of the code stays as it is.

    def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    return score


n = int(input())
words = input().split()
print(score_words(words))

  • loucifsk
     + 1 comment

    With the use of regex and list comprehension -->

    text = sys.stdin.read().splitlines()[1].split(' ')
vowels = 'aeiouy'
score = 0

for word in text:
    if len(re.findall(rf"[{vowels}]", word, flags=re.I))%2 == 0:
        score += 2
        continue
    score +=1

print(score)