We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Introduction
  4. Write a function
  5. Discussions

Write a function

Sort 1971 Discussions, By:

  • juanfelipeclsg
     + 0 comments
    def is_leap(year):
    leap = False

    # Write your logic here
    if year>=1900 and year<=10**5:
     if year%4!= 0:
       leap = False
     elif year%4==0 and year%100!=0:
       leap = True
     elif year%4==0 and year%100==0 and year%400!=0:
       leap = False
     elif year%4==0 and year%100==0 and year%400==0:
       leap = True  
    return leap
    
year = int(input())
print(is_leap(year))

  • joe_choosakul
     + 0 comments

    Three conditions are used to identify leap years: The year can be evenly divided by 4, is a leap year,

    if year % 4 == 0:
    leap == True

    Unless, the year can be evenly divided by 100, it is NOT a leap year, 

    if year % 100 == 0:
    leap == False

    Unless, the year is also evenly divisible by 400. Then it is a leap year.

    if year % 400  == 0:
    leap == True

    EXAMPLE: 

    def is_leap(year):
    leap = False
    
    # Write your logic here
    if year % 4 == 0:
        leap = True
    if year % 100 == 0:
        leap = False
    if year % 400 == 0:
        leap = True
        
    return leap
year = int(input())
print(is_leap(year))

  • lorenzo_solito
     + 0 comments

    This is a simple solution just by doing the checks and return the value of the checks (True or False):

    def is_leap(year):
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

year = int(input())
print(is_leap(year))

  • afk_puma
     + 0 comments

    Shorter solution:

    def is_leap(year): leap = False

    # Write your logic here

if year % 4 == 0 and year % 100 > 0 or year % 100 ==0 and year % 400 == 0:
    leap = True
else:
    leap


return leap

    year = int(input()) print(is_leap(year))

    return leap

    year = int(input()) print(is_leap(year))

  • aalindpathak
     + 0 comments

    write code in simple manner

    def is_leap(year): leap = False if year % 400 == 0: leap = True elif year % 100 == 0: leap = False elif year % 4 == 0: leap = True 

    return leap

    year = int(input()) print(is_leap(year))

Load more conversations