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  1. Prepare
  2. Python
  3. XML
  4. XML 1 - Find the Score
  5. Discussions

XML 1 - Find the Score

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208 Discussions

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  • dilajevolves
     + 0 comments
    import sys
import xml.etree.ElementTree as etree

def get_attr_number(node):
    return sum(len(elem.attrib) for elem in node.iter())

if __name__ == '__main__':
    sys.stdin.readline()
    xml = sys.stdin.read()
    tree = etree.ElementTree(etree.fromstring(xml))
    root = tree.getroot()
    print(get_attr_number(root))

  • maxence_qnt
     + 0 comments

    I don't know why, but I was pretty sure that we have to do recursive method to solve this problem. I mean, I did that, and it works. But when I see others solutions, I have seen that node.iter() just go through every line of the xml document which is, I think, better.

    Anyway, here my code :

    import sys
import xml.etree.ElementTree as etree

def get_attr_number(node):
    # your code goes here
    count = len(node.attrib)
           
    for child in node:
        count += get_attr_number(child)
        
    return count
    

if __name__ == '__main__':
    sys.stdin.readline()
    xml = sys.stdin.read()
    tree = etree.ElementTree(etree.fromstring(xml))
    root = tree.getroot()
    print(get_attr_number(root))

  • yashdeora98294
     + 0 comments

    Here is HackerRank XML 1 - Find the Score in Python solution - https://programmingoneonone.com/hackerrank-xml-1-find-the-score-solution-in-python.html

  • arohi_agrawal111
     + 0 comments
    import sys
import xml.etree.ElementTree as etree

def get_attr_number(node):
    count = len(node.attrib)
    for child in node:
        count += get_attr_number(child)
    return count

if __name__ == '__main__':
    sys.stdin.readline()
    xml = sys.stdin.read()
    tree = etree.ElementTree(etree.fromstring(xml))
    root = tree.getroot()
    print(get_attr_number(root))

  • singhshrajan
     + 0 comments
    1. def get_attr_number(node):
    2. count = 0
    3. for i in node.iter():
    4. count+=len(i.attrib)
    5. return count