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int main(){ int t; cin >> t; for(int a0 = 0; a0 < t; a0++){ long n; cin >> n; long long x=0,y=1,sum=0; long long total=0; while(sum<=n){ if(sum % 2==0){ total=total+sum; } sum=x+y; x=y; y=sum; } cout<<total<<endl; } return 0; }
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Project Euler #2: Even Fibonacci numbers
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