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long n1=(n*(n+1)/2);
long n2=(n*(n+1)*(2*n+1))/6;
by using this formula it give wrong out put 10000
by using normal traditonl method using loop gives correct answer is there any one discuss on this .
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Project Euler #6: Sum square difference
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long n1=(n*(n+1)/2); long n2=(n*(n+1)*(2*n+1))/6; by using this formula it give wrong out put 10000 by using normal traditonl method using loop gives correct answer is there any one discuss on this .