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solution in python 3
one_digit = {'0': '', '1': 'One', '2': 'Two', '3': 'Three', '4': 'Four', '5': 'Five', '6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine'} two_digit = {'10': 'Ten', '11': 'Eleven', '12': 'Twelve', '13': 'Thirteen', '14': 'Fourteen', '15': 'Fifteen', '16': 'Sixteen', '17': 'Seventeen', '18': 'Eighteen', '19': 'Nineteen', '2': 'Twenty', '3': 'Thirty', '4': 'Forty', '5': 'Fifty', '6': 'Sixty', '7': 'Seventy', '8': 'Eighty', '9': 'Ninety'} arzesh = {0: '', 1: 'Thousand', 2: 'Million', 3: 'Billion', 4: "Trillion"} def give_three_digit(s): # s = string containing 3 digits ans = '' if s[0] != '0': ans += one_digit[s[0]]+' '+'Hundred'+' ' if s[1] != '0' and s[1] != '1': ans += two_digit[s[1]]+' ' if s[1] == '1': ans += two_digit[s[1:]]+' ' if s[1] != '1' and s[2] != '0': ans += one_digit[s[2]]+' ' if s[1] != '1' and s[2] == '0': ans += one_digit[s[2]] return(ans) def solve(n): if n == '0': print('Zero') return num = [] ans = '' i = 0 num.append(n[:len(n) % 3]) i += (len(n) % 3) while i < len(n): num.append(n[i:i+3]) i += 3 if num[0] == '': del(num[0]) num[0] = '0'*(3-len(num[0]))+num[0] N = len(num) for i in range(N): if num[i] == '000': continue ans += give_three_digit(num[i]) ans += arzesh[N-i-1]+' ' print(ans[:len(ans)-1]) for _ in range(int(input())): solve(input())
Project Euler #17: Number to Words
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solution in python 3