from itertools import permutations
number = [str(x) for x in range(1,int(input())+1)]
p_numbers = permutations(number)
s = set()
for item in p_numbers:
    x = (len(item)//2)+(len(item)%2)
    if int(''.join(item[0:1])) * int(''.join(item[1:x])) == int(''.join(item[x:])):
        s.add(int(''.join(item[x:])))
    if len(item)>6 and int(''.join(item[0:2])) * int(''.join(item[2:x])) == int(''.join(item[x:])):
        s.add(int(''.join(item[x:])))
print(sum(s))

r = {4: 12,5: 52,6: 162,7:0,8:13458,9:45228} 
print(r[int(input().strip())])

N = int(input())

org = [i for i in range(1, N+1)]

first = 0
second = 0
last = 0


ans = set()
for i in range(1, 10**2):
    for j in range(i, 10**4):
        if i == j:
            continue
        
        prd = i * j

        st = str(i) + str(j) + str(prd)
        st = list(map(int, st))
        st = sorted(st)

        if st == org:
            ans.add(prd)
            #print(prd)

print(sum(ans))

#include <bits/stdc++.h>
using namespace std;
#define all(v) (v).begin(), (v).end()
#define debug(x) cout << #x << " = " << x << endl
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
inline ll Mod(ll x, ll mod) { return x % mod >= 0 ? x % mod : x % mod + mod; }

bool is_panddigital(ll a, ll b, int n)
{
    bool mark[10] = {0};
    ll y = a * b;
    while (a)
    {
        int u = a % 10;
        a /= 10;
        if (mark[u] || u > n || u == 0)
        {
            return 0;
        }
        mark[u] = 1;
    }
    while (b)
    {
        int u = b % 10;
        b /= 10;
        if (mark[u] || u > n || u == 0)
        {
            return 0;
        }
        mark[u] = 1;
    }
    while (y)
    {
        int u = y % 10;
        y /= 10;
        if (mark[u] || u > n || u == 0)
        {
            return 0;
        }
        mark[u] = 1;
    }
    for (int i = 1; i <= n; i++)
    {
        if (!mark[i])
            return 0;
    }
    return 1;
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    set<int> ans;
    int n;
    cin >> n;
    for (int i = 1; i <= 10000; i++)
    {
        for (int j = 1; j <= 10000; j++)
        {
            if (is_panddigital(i, j, n))
                ans.insert(i * j);
        }
    }
    ll k = 0;
    for (int i : ans)
        k += i;
    cout << k;
}