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100% python - uses qudratic formula

import math a, b, c = 1, 1, -2 for a0 in range(int(input())): N = int(input()) D = int(math.sqrt((b**2 - 4 * a * c * N))) n1, n2 = (-b-D)//(2*a), (-b+D)//(2*a) #print(N, n1, n2) if n1 > 0 and N == n1*(n1+1)//2: print(n1) elif n2> 0 and N == n2*(n2+1)//2: print(n2) else: print(-1)

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## Project Euler #42: Coded triangle numbers

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100% python - uses qudratic formula