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f(4)=3 (4,2+2,1+1+2) but f(2)=2 (2,1+1) so f(4)!=f(2)
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Project Euler #169: Exploring the number of different ways a number can be expressed as a sum of powers of 2.
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f(4)=3 (4,2+2,1+1+2) but f(2)=2 (2,1+1) so f(4)!=f(2)