Can anybody tell me what I'm missing?

# Enter your code here. Read input from STDIN. Print output to STDOUT
t = int(input().rstrip())
nums = [0]*(10**6)
col = [0]*(10**6)
max_nums = 1
nums[0] = 1

def enlarge_max(next_max):
    global max_nums
    global nums
    global col
    
    #nums[0] = 1
    #print("enlarging from {} to {}".format(max_nums, next_max))
    for i in range(1, next_max+1):
        ss = int(max_nums / i) * i
        #if ss == max_nums:
        #    nums[ss-1] += 1
        ss += i
        #print("... i={} starting ss={}".format(i, ss))
        while ss <= next_max:
            #print("   cur ss={}".format(ss))
            nums[ss-1] += 1
            ss += i
            
    #print("cur nums={}".format(nums[0:next_max]))
    #print("new max = {}".format(next_max))
    prev_col = col[max_nums-1]
    #print("    prev max = {} prev_col = {}".format(max_nums, prev_col))
    
            
    for i in range(max_nums, next_max):
        #col[i-1] = prev_col
        
        if nums[i] == nums[i+1]:
            #print("  found equality at i={} {}={}".format(i, nums[i], nums[i+1]))
            prev_col += 1
        col[i] = prev_col
    
    #print(" arr equality={}".format(col[0:next_max]))
            
            
    max_nums = next_max
        
for _ in range(0, t):
    k = int(input().rstrip())
    enlarge_max(k)
    print("{}".format(col[k-1]))

What is actully n? explaination is too short to understand the output. The only n < 15 are 2 and 14.

Can anyone tell me what am I missing?? I am able to pass test case 0 not rest of them . Please help thank you

con <- file("stdin", open = "r")
data <- as.numeric(readLines(con))

for (i in 1:data[1]){
    I <- data[i+1]
    n <- array(0,dim = I)
for (i in 1:floor((I-1)/2)){
  for (j in seq(i*2,I, by = i)){
    n[j]= n[j]+1
  } 
 }
 b <- 0
 for(i in 2:I){
  if((n[i]==n[i-1])==TRUE){
    b <- b+1
  }
 }
     cat(b,sep = "\n")
}

what the question mean i cant understand please anyone can explain the question

why my code is giving timeout canbody give a hint

include

using namespace std;

const int MAX = 10000002;

// array to store prime factors int factor[MAX] = { 0 };

// function to generate all prime factors // of numbers from 1 to 10^7 void generatePrimeFactors() { factor[1] = 1;

// Initializes all the positions with their value. 
for (int i = 2; i < MAX; i++) 
    factor[i] = i; 

// Initializes all multiples of 2 with 2 
for (int i = 4; i < MAX; i += 2) 
    factor[i] = 2; 

// A modified version of Sieve of Eratosthenes to 
// store the smallest prime factor that divides 
// every number. 
for (int i = 3; i * i < MAX; i++) { 
    // check if it has no prime factor. 
    if (factor[i] == i) { 
        // Initializes of j starting from i*i 
        for (int j = i * i; j < MAX; j += i) { 
            // if it has no prime factor before, then 
            // stores the smallest prime divisor 
            if (factor[j] == j) 
                factor[j] = i; 
        } 
    } 
} 

}

// function to calculate number of factors int calculateNoOFactors(int n) { if (n == 1) return 1;

int ans = 1; 

// stores the smallest prime number 
// that divides n 
int dup = factor[n]; 

// stores the count of number of times 
// a prime number divides n. 
int c = 1; 

// reduces to the next number after prime 
// factorization of n 
int j = n / factor[n]; 

// false when prime factorization is done 
while (j != 1) { 
    // if the same prime number is dividing n, 
    // then we increase the count 
    if (factor[j] == dup) 
        c += 1; 

    /* if its a new prime factor that is factorizing n,  
       then we again set c=1 and change dup to the new  
       prime factor, and apply the formula explained  
       above. */
    else { 
        dup = factor[j]; 
        ans = ans * (c + 1); 
        c = 1; 
    } 

    // prime factorizes a number 
    j = j / factor[j]; 
} 

// for the last prime factor 
ans = ans * (c + 1); 

return ans; 

}

// Driver program to test above function int main() { // generate prime factors of number // upto 10^7 generatePrimeFactors(); vectora(10000002); for (int i = 1; i < 10000002; i++) a[i]= calculateNoOFactors(i); vectorcount(10000001); for(int i=1;i<=10000000;i++) { if(a[i]==a[i+1]) { count[i]=count[i-1]+1; } else { count[i]=count[i-1]; }

}
int t;
scanf("%d",&t);
while(t--)
{
    int k;
    cin>>k;
    printf("%d\n",count[k-1]);
}
return 0; 

}

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