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The second example contradicts the problem description. The description states that a proper fraction is one in which the numerator is less than the denominator. But in the second example, the fraction given is '1/1', which doesn't fulfill the criteria of being a proper fraction.
phew!! at last after 4 months my code worked!! learned a lot with this challenge
I don't understand what should I do with T?
when p = 1/10, the answer is near 1.6516447 * 10^103
I hope this infomation will help you
is there a way to see the test cases? dont understand why I cant pass more than two