function absolutePermutation(n, k) {
  let a = [];
  for (let i = 1; i <= n; i++) {
    a.push(i);
  }
  k = Math.abs(k);
  if (k == 0) return a;
  else if (k > n / 2 + 1 || n % k != 0 || (n/k % 2 != 0)) return [-1];
  else {
    a = [];
    for (let i = 1; i <= n; i++) {
      a.push(i + Math.pow(-1, Math.floor((i - 0.1) / k)) * k);
    }
    return a;
  }
}