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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Angry Professor
  5. Discussions

Angry Professor

  • gandymovspc
     + 0 comments

    Here is my solution in JavaScript

    let onTime = 0;
for(let i = 0; i < a.length; i++){
	if(a[i] <= 0){
		onTime++
	}
}
return onTime < k ? "YES" : "NO"