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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Apple and Orange
  5. Discussions

Apple and Orange

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  • shashantlbartwal
     + 0 comments

    func countApplesAndOranges(s: Int, t: Int, a: Int, b: Int, apples: [Int], oranges: [Int]) -> Void { let appleNewPos = apples.map { val in return val+a }.filter { val in val>=s && val<=t } let orangeNewPos = oranges.map { val in return val+b }.filter { val in val>=s && val<=t } print("(appleNewPos.count)") print("(orangeNewPos.count)") }

  • nicokurtz01
     + 0 comments
    void countApplesAndOranges(int s, int t, int a, int b, vector<int> apples, vector<int> oranges) {
    // get the coordinates of the fallen fruits and check whether they are in [s, t]
    std::transform(apples.begin(), apples.end(), apples.begin(),
    [a,s,t] (int d) {
        return (a + d >= s && a + d <= t) ? 1 : 0;     
    });
    std::transform(oranges.begin(), oranges.end(), oranges.begin(),
    [b,s,t] (int d) {
       return (b + d >= s && b + d <= t) ? 1 : 0; 
    });
    
    // then just sum up the elements and print the result
    std::cout << std::accumulate(apples.begin(), apples.end(), 0) << std::endl;
    std::cout << std::accumulate(oranges.begin(), oranges.end(), 0) << std::endl;
}

  • kancharla_vardh1
     + 0 comments

    public static void countApplesAndOranges(int s, int t, int a, int b, List apples, List oranges) { // Write your code here long ab = apples.stream().map(n->n+a).filter(n->(n>=s && n<=t)).count(); System.out.println(ab); long bc = oranges.stream().map(n->n+b).filter(n->(n>=s && n<=t)).count(); System.out.println(bc); }

  • alex_clapou
     + 0 comments

    Ruby

    def countApplesAndOranges(s, t, a, b, apples, oranges)
  land_on_house = lambda { |value| value.between?(s, t) }

  puts apples.count {|apple| land_on_house.(apple + a)}
  puts oranges.count {|orange| land_on_house.(orange + b)}
end

  • fran_delgado_ca1
     + 0 comments

    My JS solution:

    function countApplesAndOranges(s, t, a, b, apples, oranges) {
    console.log(
        apples
            .map(apple => apple + a)
            .filter(apple => apple >= s && t >= apple).length
        );
    console.log(
        oranges
            .map(orange => b + orange)
            .filter(orange => orange <= t && orange >= s).length
        );
}