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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Apple and Orange
  5. Discussions

Apple and Orange

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3130 Discussions

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  • mariocgf
     + 0 comments

    Mi solucion en C# con bucle y LINQ

    public static void countApplesAndOranges(int s, int t, int a, int b, List<int> apples, List<int> oranges)
    {
        int countApple = 0, countOrange = 0;
        foreach(int apple in apples){
            if((apple + a) >= s && (apple + a) <=t){
                countApple++;
            }
        }
        countOrange = oranges.Count(orange => (b + orange) >= s && (b + orange) <=t);

        Console.WriteLine($"{countApple}\n{countOrange}");
    }

  • luisagabrielahp
     + 0 comments

    Mi solución en Python 3:

    def countApplesAndOranges(s, t, a, b, apples, oranges):
    # Write your code here 
    man = 0
    nar = 0

    for i in apples:
        if a+i in range(s,t+1):
            man += 1
    for j in oranges:
        if b+j in range(s,t+1):
            nar += 1
    print (man)
    print (nar)

  • kenliu092
     + 0 comments

    def countApplesAndOranges(s, t, a, b, apples, oranges): line1 = 0 line2 = 0

    for i in range(m):
    if t >= (apples[i] + a) >= s:
        line1 += 1

for j in range(n):
    if t >= (oranges[j] + b) >= s:
        line2 += 1

print(line1)
print(line2)

  • jrarjundev
     + 0 comments

    co=0 for i in apples : if(i+a)>=s and (i+a)<=t: ca+=1 for i in oranges : if(i+b)>=s and (i+b)<=t: co+=1 print(ca) print(co)

    • ****

  • jrarjundev
     + 0 comments

    co=0 for i in apples : if(i+a)>=s and (i+a)<=t: ca+=1 for i in oranges : if(i+b)>=s and (i+b)<=t: co+=1 print(ca) print(co)

        ****