We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Algorithms
  3. Implementation
  4. Apple and Orange
  5. Discussions

Apple and Orange

Sort by

recency

|

3087 Discussions

|

  • fran_delgado_ca1
     + 0 comments

    My JS solution:

    function countApplesAndOranges(s, t, a, b, apples, oranges) {
    console.log(
        apples
            .map(apple => apple + a)
            .filter(apple => apple >= s && t >= apple).length
        );
    console.log(
        oranges
            .map(orange => b + orange)
            .filter(orange => orange <= t && orange >= s).length
        );
}

  • wmgarciaporcel
     + 0 comments

    This is my approach:

    function countApplesAndOranges(s, t, a, b, apples, oranges) {
    // Write your code here
    let counter = [0,0];
        
    apples.map(ap=>{
        if(((ap+a)>=s)&&((ap+a)<=t)) counter[0] ++;
    })
    oranges.map(or=>{
        if(((or+b)>=s)&&((or+b)<=t)) counter[1] ++;
    })
    return console.log(counter.join('\n'));
}

  • 2050yadavankit
     + 0 comments

    THIS IS MY PYTHON CODE:

    #!/bin/python3

import math
import os
import random
import re
import sys

#
# Complete the 'countApplesAndOranges' function below.
#
# The function accepts following parameters:
#  1. INTEGER s
#  2. INTEGER t
#  3. INTEGER a
#  4. INTEGER b
#  5. INTEGER_ARRAY apples
#  6. INTEGER_ARRAY oranges
#

def countApplesAndOranges(s, t, a, b, apples, oranges):
    apple_count = 0
    orange_count = 0

    for d in apples:
        if s <= a + d <= t:
            apple_count += 1

    for d in oranges:
        if s <= b + d <= t:
            orange_count += 1

    print(apple_count)
    print(orange_count)

if __name__ == '__main__':
    first_multiple_input = input().rstrip().split()
    s = int(first_multiple_input[0])
    t = int(first_multiple_input[1])

    second_multiple_input = input().rstrip().split()
    a = int(second_multiple_input[0])
    b = int(second_multiple_input[1])

    third_multiple_input = input().rstrip().split()
    m = int(third_multiple_input[0])
    n = int(third_multiple_input[1])

    apples = list(map(int, input().rstrip().split()))
    oranges = list(map(int, input().rstrip().split()))

    countApplesAndOranges(s, t, a, b, apples, oranges)

  • ialexalionline
     + 0 comments

    The simplest way is using BeautyPlus—an AI-powered tool that lets you effortlessly clean up photos. Just paint over unwanted objects or people, and they disappear in seconds, leaving a flawless image. Whether it’s photobombers, blemishes, or distracting backgrounds, BeautyPlus’s AI Object Remover handles it seamlessly. No complex editing skills needed! Plus, it works on both quick touch-ups and detailed edits. Ideal for social media, professional shots, or personal memories, this tool ensures polished results every time. Try https://www.beautyplus.com/object-remover it to see how easily you can remove parts of the image and enhance your photos with just a few taps!

  • rounakvhaskeri
     + 0 comments

    C Programming Solution:

    void countApplesAndOranges(int s, int t, int a, int b, int apples_count, int* apples, int oranges_count, int* oranges) {
    int count[2]={0,0};
    for(int i=0; i<2;i++){
        if(i==0){
            for(int j=0; j<apples_count;j++){
                if((a+apples[j])>=s && (a+apples[j])<=t ){
                    (count[i])++;
                }
            }
        }
        else{
            for(int j=0; j<oranges_count;j++){
                if((b+oranges[j])>=s && (b+oranges[j])<=t ){
                    (count[i])++;
                }
            }
        }
    }
    printf("%d\n%d",count[0],count[1]);
}